43g^2+40g=0

Solution for 43g^2+40g=0 equation:

43g^2+40g=0

a = 43; b = 40; c = 0;
Δ = b2-4ac
Δ = 402-4·43·0
Δ = 1600
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$g_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$g_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{1600}=40$
$g_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(40)-40}{2*43}=\frac{-80}{86}
=-40/43
$
$g_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(40)+40}{2*43}=\frac{0}{86}
=0
$